The Numbers Are All the Numbers

If we add up all the digits, if the sum is divisible by three, the numbers divisible by 3. There's no way that's true for all. What for all? If you just keep going, eventually you're going to sum to som that's not divisible byThree. Buti tust ruin your conjecture that yor whole conjecture was t i know the numbers are all the numbers. So we just this pook. That's what i'm seeing. Zero pattern. But they're all divisable by three, except for the first two. Except for the first 2, they're all Divisible by Three. I don't see how it could be any other